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1312241340403 = 71859310082453
BaseRepresentation
bin10011000110000111101…
…011011100111111110011
311122110010100120222101001
4103012013223130333303
5132444432240343103
62442500234022431
7163543364232430
oct23060753347763
94573110528331
101312241340403
11466578032444
121923a2b77a17
139698925bc26
144772726ab87
152420396901d
hex13187adcff3

1312241340403 has 8 divisors (see below), whose sum is σ = 1499785197408. Its totient is φ = 1124717685504.

The previous prime is 1312241340317. The next prime is 1312241340407. The reversal of 1312241340403 is 3040431422131.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1312241340403 - 213 = 1312241332211 is a prime.

It is a super-3 number, since 3×13122413404033 (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1312241340407) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4911076 + ... + 5171377.

It is an arithmetic number, because the mean of its divisors is an integer number (187473149676).

Almost surely, 21312241340403 is an apocalyptic number.

1312241340403 is a deficient number, since it is larger than the sum of its proper divisors (187543857005).

1312241340403 is a wasteful number, since it uses less digits than its factorization.

1312241340403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10101053.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1312241340403 its reverse (3040431422131), we get a palindrome (4352672762534).

The spelling of 1312241340403 in words is "one trillion, three hundred twelve billion, two hundred forty-one million, three hundred forty thousand, four hundred three".

Divisors: 1 7 18593 130151 10082453 70577171 187463048629 1312241340403