Base | Representation |
---|---|
bin | 1011111011110100110011… |
… | …0011000110000110110011 |
3 | 1201110111020120012021202122 |
4 | 2332331030303012012303 |
5 | 3204444200332131201 |
6 | 43524204211504455 |
7 | 2523030432542606 |
oct | 276751463060663 |
9 | 51414216167678 |
10 | 13122413552051 |
11 | 41aa203393231 |
12 | 157b2658b812b |
13 | 742590bc499b |
14 | 3351b1b1833d |
15 | 17b52648de1b |
hex | bef4ccc61b3 |
13122413552051 has 8 divisors (see below), whose sum is σ = 13317508028160. Its totient is φ = 12928199864392.
The previous prime is 13122413552009. The next prime is 13122413552107. The reversal of 13122413552051 is 15025531422131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13122413552051 - 242 = 8724367040947 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13122413552951) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 220167095 + ... + 220226688.
It is an arithmetic number, because the mean of its divisors is an integer number (1664688503520).
Almost surely, 213122413552051 is an apocalyptic number.
13122413552051 is a deficient number, since it is larger than the sum of its proper divisors (195094476109).
13122413552051 is an equidigital number, since it uses as much as digits as its factorization.
13122413552051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 440394225.
The product of its (nonzero) digits is 36000, while the sum is 35.
Adding to 13122413552051 its reverse (15025531422131), we get a palindrome (28147944974182).
The spelling of 13122413552051 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirteen million, five hundred fifty-two thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •