Base | Representation |
---|---|
bin | 1011111011110100110011… |
… | …0011000110000110110010 |
3 | 1201110111020120012021202121 |
4 | 2332331030303012012302 |
5 | 3204444200332131200 |
6 | 43524204211504454 |
7 | 2523030432542605 |
oct | 276751463060662 |
9 | 51414216167677 |
10 | 13122413552050 |
11 | 41aa203393230 |
12 | 157b2658b812a |
13 | 742590bc499a |
14 | 3351b1b1833c |
15 | 17b52648de1a |
hex | bef4ccc61b2 |
13122413552050 has 24 divisors (see below), whose sum is σ = 26626570044912. Its totient is φ = 4771786746000.
The previous prime is 13122413552009. The next prime is 13122413552107. The reversal of 13122413552050 is 5025531422131.
It is a junction number, because it is equal to n+sod(n) for n = 13122413551997 and 13122413552015.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 11929466316 + ... + 11929467415.
It is an arithmetic number, because the mean of its divisors is an integer number (1109440418538).
Almost surely, 213122413552050 is an apocalyptic number.
13122413552050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13122413552050 is an abundant number, since it is smaller than the sum of its proper divisors (13504156492862).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13122413552050 is a wasteful number, since it uses less digits than its factorization.
13122413552050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23858933754 (or 23858933749 counting only the distinct ones).
The product of its (nonzero) digits is 36000, while the sum is 34.
Adding to 13122413552050 its reverse (5025531422131), we get a palindrome (18147944974181).
The spelling of 13122413552050 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirteen million, five hundred fifty-two thousand, fifty".
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