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1312243101002 = 2656121550501
BaseRepresentation
bin10011000110000111110…
…010001010110101001010
311122110010110220102110102
4103012013302022311022
5132444433213213002
62442500335445402
7163543415214401
oct23060762126512
94573113812412
101312243101002
11466579025189
121923a3686862
13969897273c2
14477275a8638
1524203bb5a02
hex13187c8ad4a

1312243101002 has 4 divisors (see below), whose sum is σ = 1968364651506. Its totient is φ = 656121550500.

The previous prime is 1312243100989. The next prime is 1312243101019. The reversal of 1312243101002 is 2001013422131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 980018821681 + 332224279321 = 989959^2 + 576389^2 .

It is a super-2 number, since 2×13122431010022 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328060775249 + ... + 328060775252.

Almost surely, 21312243101002 is an apocalyptic number.

1312243101002 is a deficient number, since it is larger than the sum of its proper divisors (656121550504).

1312243101002 is an equidigital number, since it uses as much as digits as its factorization.

1312243101002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 656121550503.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1312243101002 its reverse (2001013422131), we get a palindrome (3313256523133).

The spelling of 1312243101002 in words is "one trillion, three hundred twelve billion, two hundred forty-three million, one hundred one thousand, two".

Divisors: 1 2 656121550501 1312243101002