Base | Representation |
---|---|
bin | 1011111011110100111000… |
… | …0001111001100011111011 |
3 | 1201110111022000001211012110 |
4 | 2332331032001321203323 |
5 | 3204444221124210133 |
6 | 43524210230343403 |
7 | 2523031103252154 |
oct | 276751601714373 |
9 | 51414260054173 |
10 | 13122434210043 |
11 | 41aa214012954 |
12 | 157b2707bab63 |
13 | 742595278752 |
14 | 3351b477492b |
15 | 17b5281bec63 |
hex | bef4e0798fb |
13122434210043 has 4 divisors (see below), whose sum is σ = 17496578946728. Its totient is φ = 8748289473360.
The previous prime is 13122434209987. The next prime is 13122434210077. The reversal of 13122434210043 is 34001243422131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13122434210043 - 29 = 13122434209531 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13122434210143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2187072368338 + ... + 2187072368343.
It is an arithmetic number, because the mean of its divisors is an integer number (4374144736682).
Almost surely, 213122434210043 is an apocalyptic number.
13122434210043 is a deficient number, since it is larger than the sum of its proper divisors (4374144736685).
13122434210043 is an equidigital number, since it uses as much as digits as its factorization.
13122434210043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4374144736684.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 13122434210043 its reverse (34001243422131), we get a palindrome (47123677632174).
The spelling of 13122434210043 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirty-four million, two hundred ten thousand, forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •