Base | Representation |
---|---|
bin | 1011111011110100111100… |
… | …0010111000000000100001 |
3 | 1201110111100012010012002020 |
4 | 2332331033002320000201 |
5 | 3204444240004234131 |
6 | 43524212035412053 |
7 | 2523031401113100 |
oct | 276751702700041 |
9 | 51414305105066 |
10 | 13122451243041 |
11 | 41aa222697008 |
12 | 157b276454029 |
13 | 74259896054a |
14 | 3351b6b2a037 |
15 | 17b529936996 |
hex | bef4f0b8021 |
13122451243041 has 24 divisors (see below), whose sum is σ = 20372592391200. Its totient is φ = 7491395201472.
The previous prime is 13122451243009. The next prime is 13122451243043. The reversal of 13122451243041 is 14034215422131.
It is not a de Polignac number, because 13122451243041 - 25 = 13122451243009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13122451242993 and 13122451243011.
It is not an unprimeable number, because it can be changed into a prime (13122451243043) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 42395071 + ... + 42703476.
It is an arithmetic number, because the mean of its divisors is an integer number (848858016300).
Almost surely, 213122451243041 is an apocalyptic number.
It is an amenable number.
13122451243041 is a deficient number, since it is larger than the sum of its proper divisors (7250141148159).
13122451243041 is a wasteful number, since it uses less digits than its factorization.
13122451243041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 85099613 (or 85099606 counting only the distinct ones).
The product of its (nonzero) digits is 23040, while the sum is 33.
Adding to 13122451243041 its reverse (14034215422131), we get a palindrome (27156666665172).
The spelling of 13122451243041 in words is "thirteen trillion, one hundred twenty-two billion, four hundred fifty-one million, two hundred forty-three thousand, forty-one".
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