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13123014213 = 34374338071
BaseRepresentation
bin11000011100011000…
…10100111001000101
31020212120021012020110
430032030110321011
5203333442423323
610010103423233
7643125531441
oct141614247105
936776235213
1013123014213
1156246658a1
122662a54b19
131311a1288a
148c6c2b821
1551c150793
hex30e314e45

13123014213 has 4 divisors (see below), whose sum is σ = 17497352288. Its totient is φ = 8748676140.

The previous prime is 13123014169. The next prime is 13123014227. The reversal of 13123014213 is 31241032131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-13123014213 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13123014213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13123014253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2187169033 + ... + 2187169038.

It is an arithmetic number, because the mean of its divisors is an integer number (4374338072).

Almost surely, 213123014213 is an apocalyptic number.

It is an amenable number.

13123014213 is a deficient number, since it is larger than the sum of its proper divisors (4374338075).

13123014213 is an equidigital number, since it uses as much as digits as its factorization.

13123014213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4374338074.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13123014213 its reverse (31241032131), we get a palindrome (44364046344).

The spelling of 13123014213 in words is "thirteen billion, one hundred twenty-three million, fourteen thousand, two hundred thirteen".

Divisors: 1 3 4374338071 13123014213