Base | Representation |
---|---|
bin | 1011111011110111000111… |
… | …0010000111011101010010 |
3 | 1201110112211210202222021022 |
4 | 2332331301302013131102 |
5 | 3210001433204134214 |
6 | 43524345535155442 |
7 | 2523052005653615 |
oct | 276756162073522 |
9 | 51415753688238 |
10 | 13123034052434 |
11 | 41aa4a1673369 |
12 | 157b3b9675b82 |
13 | 74265c61a687 |
14 | 3352302ba17c |
15 | 17b560baad8e |
hex | bef71c87752 |
13123034052434 has 16 divisors (see below), whose sum is σ = 19721168954136. Its totient is φ = 6549312595200.
The previous prime is 13123034052389. The next prime is 13123034052463. The reversal of 13123034052434 is 43425043032131.
It can be written as a sum of positive squares in 4 ways, for example, as 6751968387025 + 6371065665409 = 2598455^2 + 2524097^2 .
It is a super-2 number, since 2×131230340524342 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13123034052394 and 13123034052403.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17184044 + ... + 17931464.
Almost surely, 213123034052434 is an apocalyptic number.
13123034052434 is a deficient number, since it is larger than the sum of its proper divisors (6598134901702).
13123034052434 is a wasteful number, since it uses less digits than its factorization.
13123034052434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 763741.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 13123034052434 its reverse (43425043032131), we get a palindrome (56548077084565).
The spelling of 13123034052434 in words is "thirteen trillion, one hundred twenty-three billion, thirty-four million, fifty-two thousand, four hundred thirty-four".
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