13123047653819 has 4 divisors (see below), whose sum is σ = 13162694323800. Its totient is φ = 13083400983840.

The previous prime is 13123047653803. The next prime is 13123047653839. The reversal of 13123047653819 is 91835674032131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13123047653819 - 2⁴ = 13123047653803 is a prime.

It is a super-2 number, since 2×13123047653819² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13123047653839) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19823334494 + ... + 19823335155.

It is an arithmetic number, because the mean of its divisors is an integer number (3290673580950).

It is a 1-persistent number, because it is pandigital, but 2⋅13123047653819 = 26246095307638 is not.

Almost surely, 2^{13123047653819} is an apocalyptic number.

13123047653819 is a deficient number, since it is larger than the sum of its proper divisors (39646669981).

13123047653819 is an equidigital number, since it uses as much as digits as its factorization.

13123047653819 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39646669980.

The product of its (nonzero) digits is 3265920, while the sum is 53.

The spelling of 13123047653819 in words is "thirteen trillion, one hundred twenty-three billion, forty-seven million, six hundred fifty-three thousand, eight hundred nineteen".