Base | Representation |
---|---|
bin | 10011000110001011011… |
… | …111000101000100111011 |
3 | 11122110021210202122220100 |
4 | 103012023133011010323 |
5 | 133000100113034223 |
6 | 2442510434530443 |
7 | 163545101125302 |
oct | 23061337050473 |
9 | 4573253678810 |
10 | 1312305205563 |
11 | 466600093270 |
12 | 192400436a23 |
13 | 96999560271 |
14 | 47731933439 |
15 | 24209382043 |
hex | 1318b7c513b |
1312305205563 has 48 divisors (see below), whose sum is σ = 2089275084000. Its totient is φ = 787144227840.
The previous prime is 1312305205499. The next prime is 1312305205571. The reversal of 1312305205563 is 3655025032131.
1312305205563 is a `hidden beast` number, since 1 + 3 + 1 + 23 + 0 + 520 + 55 + 63 = 666.
It is not a de Polignac number, because 1312305205563 - 26 = 1312305205499 is a prime.
It is a super-2 number, since 2×13123052055632 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1312305205963) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3925443 + ... + 4246611.
It is an arithmetic number, because the mean of its divisors is an integer number (43526564250).
Almost surely, 21312305205563 is an apocalyptic number.
1312305205563 is a deficient number, since it is larger than the sum of its proper divisors (776969878437).
1312305205563 is a wasteful number, since it uses less digits than its factorization.
1312305205563 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 321612 (or 321609 counting only the distinct ones).
The product of its (nonzero) digits is 81000, while the sum is 36.
The spelling of 1312305205563 in words is "one trillion, three hundred twelve billion, three hundred five million, two hundred five thousand, five hundred sixty-three".
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