Base | Representation |
---|---|
bin | 1011111011110111011001… |
… | …1000011100110000010010 |
3 | 1201110120001011221222120000 |
4 | 2332331312120130300102 |
5 | 3210002112432210002 |
6 | 43524401333030430 |
7 | 2523053633541033 |
oct | 276756630346022 |
9 | 51416034858500 |
10 | 13123111210002 |
11 | 41aa531182a52 |
12 | 157b41b485416 |
13 | 7426725c4041 |
14 | 33523a642a8a |
15 | 17b56784c61c |
hex | bef7661cc12 |
13123111210002 has 20 divisors (see below), whose sum is σ = 29405489933886. Its totient is φ = 4374370403280.
The previous prime is 13123111209931. The next prime is 13123111210019. The reversal of 13123111210002 is 20001211132131.
It can be written as a sum of positive squares in only one way, i.e., 7391487375441 + 5731623834561 = 2718729^2 + 2394081^2 .
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 40503429499 + ... + 40503429822.
Almost surely, 213123111210002 is an apocalyptic number.
13123111210002 is an abundant number, since it is smaller than the sum of its proper divisors (16282378723884).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13123111210002 is an equidigital number, since it uses as much as digits as its factorization.
13123111210002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81006859335 (or 81006859326 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 13123111210002 its reverse (20001211132131), we get a palindrome (33124322342133).
The spelling of 13123111210002 in words is "thirteen trillion, one hundred twenty-three billion, one hundred eleven million, two hundred ten thousand, two".
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