131231410421431 has 4 divisors (see below), whose sum is σ = 131241708747792. Its totient is φ = 131221112095072.

The previous prime is 131231410421389. The next prime is 131231410421473. The reversal of 131231410421431 is 134124014132131.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (131231410421389) and next prime (131231410421473).

It is a cyclic number.

It is not a de Polignac number, because 131231410421431 - 2³⁵ = 131197050683063 is a prime.

It is a super-2 number, since 2×131231410421431² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131231410421393 and 131231410421402.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131231410424431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5149144066 + ... + 5149169551.

It is an arithmetic number, because the mean of its divisors is an integer number (32810427186948).

Almost surely, 2^{131231410421431} is an apocalyptic number.

131231410421431 is a deficient number, since it is larger than the sum of its proper divisors (10298326361).

131231410421431 is a wasteful number, since it uses less digits than its factorization.

131231410421431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10298326360.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 131231410421431 its reverse (134124014132131), we get a palindrome (265355424553562).

The spelling of 131231410421431 in words is "one hundred thirty-one trillion, two hundred thirty-one billion, four hundred ten million, four hundred twenty-one thousand, four hundred thirty-one".