Base | Representation |
---|---|
bin | 11101110101101011011101… |
… | …000111001110100100011011 |
3 | 122012122200002111120222022011 |
4 | 131311223131013032210123 |
5 | 114200101410421441103 |
6 | 1143035114003210351 |
7 | 36433131530402140 |
oct | 3565533507164433 |
9 | 565580074528264 |
10 | 131232140421403 |
11 | 388a626906465a |
12 | 128758023769b7 |
13 | 582c1a3806408 |
14 | 24599531003c7 |
15 | 10289b0c5bd6d |
hex | 775add1ce91b |
131232140421403 has 16 divisors (see below), whose sum is σ = 150110063182336. Its totient is φ = 112386839273280.
The previous prime is 131232140421377. The next prime is 131232140421461. The reversal of 131232140421403 is 304124041232131.
It is a happy number.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131232140421403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131232140421203) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 901785775 + ... + 901931287.
It is an arithmetic number, because the mean of its divisors is an integer number (9381878948896).
Almost surely, 2131232140421403 is an apocalyptic number.
131232140421403 is a deficient number, since it is larger than the sum of its proper divisors (18877922760933).
131232140421403 is a wasteful number, since it uses less digits than its factorization.
131232140421403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 256714.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 131232140421403 its reverse (304124041232131), we get a palindrome (435356181653534).
The spelling of 131232140421403 in words is "one hundred thirty-one trillion, two hundred thirty-two billion, one hundred forty million, four hundred twenty-one thousand, four hundred three".
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