Base | Representation |
---|---|
bin | 11101110101101011101110… |
… | …011101010011011011010101 |
3 | 122012122200211210011021220020 |
4 | 131311223232131103123111 |
5 | 114200103004420434031 |
6 | 1143035202520255353 |
7 | 36433141663014651 |
oct | 3565535635233325 |
9 | 565580753137806 |
10 | 131232431421141 |
11 | 388a63a8351006 |
12 | 12875883911559 |
13 | 582c21bba26cb |
14 | 245997da0da61 |
15 | 10289cb58e096 |
hex | 775aee7536d5 |
131232431421141 has 8 divisors (see below), whose sum is σ = 174976781706240. Its totient is φ = 87488184375072.
The previous prime is 131232431421137. The next prime is 131232431421197. The reversal of 131232431421141 is 141124134232131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 131232431421141 - 22 = 131232431421137 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131232431411141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22793376 + ... + 27964313.
It is an arithmetic number, because the mean of its divisors is an integer number (21872097713280).
Almost surely, 2131232431421141 is an apocalyptic number.
It is an amenable number.
131232431421141 is a deficient number, since it is larger than the sum of its proper divisors (43744350285099).
131232431421141 is an equidigital number, since it uses as much as digits as its factorization.
131232431421141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51619515.
The product of its digits is 13824, while the sum is 33.
Adding to 131232431421141 its reverse (141124134232131), we get a palindrome (272356565653272).
The spelling of 131232431421141 in words is "one hundred thirty-one trillion, two hundred thirty-two billion, four hundred thirty-one million, four hundred twenty-one thousand, one hundred forty-one".
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