Base | Representation |
---|---|
bin | 1011111011111000000110… |
… | …1000101011000000001001 |
3 | 1201110120112100020010021010 |
4 | 2332332001220223000021 |
5 | 3210003004300341131 |
6 | 43524432155434133 |
7 | 2523061415406222 |
oct | 276760150530011 |
9 | 51416470203233 |
10 | 13123300012041 |
11 | 41aa61880779a |
12 | 157b472755949 |
13 | 7426a275a41b |
14 | 33525774c249 |
15 | 17b5791e3b46 |
hex | bef81a2b009 |
13123300012041 has 8 divisors (see below), whose sum is σ = 17500607036640. Its totient is φ = 8747429831072.
The previous prime is 13123300012013. The next prime is 13123300012051. The reversal of 13123300012041 is 14021000332131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13123300012041 - 214 = 13123299995657 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13123300011999 and 13123300012017.
It is not an unprimeable number, because it can be changed into a prime (13123300012051) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 359189595 + ... + 359226128.
It is an arithmetic number, because the mean of its divisors is an integer number (2187575879580).
Almost surely, 213123300012041 is an apocalyptic number.
It is an amenable number.
13123300012041 is a deficient number, since it is larger than the sum of its proper divisors (4377307024599).
13123300012041 is an equidigital number, since it uses as much as digits as its factorization.
13123300012041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 718421815.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13123300012041 its reverse (14021000332131), we get a palindrome (27144300344172).
The spelling of 13123300012041 in words is "thirteen trillion, one hundred twenty-three billion, three hundred million, twelve thousand, forty-one".
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