Base | Representation |
---|---|
bin | 1011111011111000000110… |
… | …1000101011000000010011 |
3 | 1201110120112100020010021111 |
4 | 2332332001220223000103 |
5 | 3210003004300341201 |
6 | 43524432155434151 |
7 | 2523061415406235 |
oct | 276760150530023 |
9 | 51416470203244 |
10 | 13123300012051 |
11 | 41aa6188077a9 |
12 | 157b472755957 |
13 | 7426a275a428 |
14 | 33525774c255 |
15 | 17b5791e3b51 |
hex | bef81a2b013 |
13123300012051 has 2 divisors, whose sum is σ = 13123300012052. Its totient is φ = 13123300012050.
The previous prime is 13123300012013. The next prime is 13123300012057. The reversal of 13123300012051 is 15021000332131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13123300012051 - 225 = 13123266457619 is a prime.
It is not a weakly prime, because it can be changed into another prime (13123300012057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561650006025 + 6561650006026.
It is an arithmetic number, because the mean of its divisors is an integer number (6561650006026).
Almost surely, 213123300012051 is an apocalyptic number.
13123300012051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123300012051 is an equidigital number, since it uses as much as digits as its factorization.
13123300012051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 13123300012051 its reverse (15021000332131), we get a palindrome (28144300344182).
The spelling of 13123300012051 in words is "thirteen trillion, one hundred twenty-three billion, three hundred million, twelve thousand, fifty-one".
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