Search a number
-
+
13123311515245 = 52624662303049
BaseRepresentation
bin1011111011111000001001…
…0100100011011001101101
31201110120120010212112200201
42332332002110203121231
53210003020221441440
643524433250153501
72523061615236241
oct276760224433155
951416503775621
1013123311515245
1141aa624254278
12157b476582891
137426a4c57259
143352590a4421
1517b57a21719a
hexbef8252366d

13123311515245 has 4 divisors (see below), whose sum is σ = 15747973818300. Its totient is φ = 10498649212192.

The previous prime is 13123311515203. The next prime is 13123311515261. The reversal of 13123311515245 is 54251511332131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10153055740996 + 2970255774249 = 3186386^2 + 1723443^2 .

It is a cyclic number.

It is not a de Polignac number, because 13123311515245 - 231 = 13121164031597 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1312331151520 + ... + 1312331151529.

It is an arithmetic number, because the mean of its divisors is an integer number (3936993454575).

Almost surely, 213123311515245 is an apocalyptic number.

It is an amenable number.

13123311515245 is a deficient number, since it is larger than the sum of its proper divisors (2624662303055).

13123311515245 is an equidigital number, since it uses as much as digits as its factorization.

13123311515245 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2624662303054.

The product of its digits is 54000, while the sum is 37.

Adding to 13123311515245 its reverse (54251511332131), we get a palindrome (67374822847376).

The spelling of 13123311515245 in words is "thirteen trillion, one hundred twenty-three billion, three hundred eleven million, five hundred fifteen thousand, two hundred forty-five".

Divisors: 1 5 2624662303049 13123311515245