Base | Representation |
---|---|
bin | 111101000111000011… |
… | …1110100011000110101 |
3 | 110112201212212010210202 |
4 | 1322032013310120311 |
5 | 4122231224330031 |
6 | 140142055530245 |
7 | 12324041530226 |
oct | 1721607643065 |
9 | 415655763722 |
10 | 131233433141 |
11 | 50723940768 |
12 | 21525989985 |
13 | c4b55a3825 |
14 | 64cd21d24d |
15 | 36312a52cb |
hex | 1e8e1f4635 |
131233433141 has 4 divisors (see below), whose sum is σ = 131272692672. Its totient is φ = 131194173612.
The previous prime is 131233433131. The next prime is 131233433153. The reversal of 131233433141 is 141334332131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131233433141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131233433101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19624751 + ... + 19631436.
It is an arithmetic number, because the mean of its divisors is an integer number (32818173168).
Almost surely, 2131233433141 is an apocalyptic number.
It is an amenable number.
131233433141 is a deficient number, since it is larger than the sum of its proper divisors (39259531).
131233433141 is an equidigital number, since it uses as much as digits as its factorization.
131233433141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39259530.
The product of its digits is 7776, while the sum is 29.
Adding to 131233433141 its reverse (141334332131), we get a palindrome (272567765272).
The spelling of 131233433141 in words is "one hundred thirty-one billion, two hundred thirty-three million, four hundred thirty-three thousand, one hundred forty-one".
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