13123443300551 has 4 divisors (see below), whose sum is σ = 13132601322432. Its totient is φ = 13114285278672.

The previous prime is 13123443300547. The next prime is 13123443300589. The reversal of 13123443300551 is 15500334432131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13123443300551 - 2² = 13123443300547 is a prime.

It is a super-3 number, since 3×13123443300551³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13123443305551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4579008791 + ... + 4579011656.

It is an arithmetic number, because the mean of its divisors is an integer number (3283150330608).

Almost surely, 2^{13123443300551} is an apocalyptic number.

13123443300551 is a deficient number, since it is larger than the sum of its proper divisors (9158021881).

13123443300551 is an equidigital number, since it uses as much as digits as its factorization.

13123443300551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9158021880.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 13123443300551 its reverse (15500334432131), we get a palindrome (28623777732682).

The spelling of 13123443300551 in words is "thirteen trillion, one hundred twenty-three billion, four hundred forty-three million, three hundred thousand, five hundred fifty-one".