Base | Representation |
---|---|
bin | 1011111011111000101010… |
… | …0110101111101110010011 |
3 | 1201110120220211101210201121 |
4 | 2332332022212233232103 |
5 | 3210003311312031120 |
6 | 43524455133143111 |
7 | 2523065223506446 |
oct | 276761246575623 |
9 | 51416824353647 |
10 | 13123450502035 |
11 | 41aa695754095 |
12 | 157b4b502aa97 |
13 | 7426c799b363 |
14 | 33526d72365d |
15 | 17b58751d5aa |
hex | bef8a9afb93 |
13123450502035 has 8 divisors (see below), whose sum is σ = 15749390431296. Its totient is φ = 10497927182400.
The previous prime is 13123450502023. The next prime is 13123450502069. The reversal of 13123450502035 is 53020505432131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-13123450502035 is a prime.
It is a super-4 number, since 4×131234505020354 (a number of 54 digits) contains 4444 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 104083099 + ... + 104209108.
It is an arithmetic number, because the mean of its divisors is an integer number (1968673803912).
Almost surely, 213123450502035 is an apocalyptic number.
13123450502035 is a deficient number, since it is larger than the sum of its proper divisors (2625939929261).
13123450502035 is a wasteful number, since it uses less digits than its factorization.
13123450502035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 208304813.
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 13123450502035 its reverse (53020505432131), we get a palindrome (66143955934166).
The spelling of 13123450502035 in words is "thirteen trillion, one hundred twenty-three billion, four hundred fifty million, five hundred two thousand, thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •