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13123450502634 = 2318041121237279
BaseRepresentation
bin1011111011111000101010…
…0110101111110111101010
31201110120220211101211112210
42332332022212233313222
53210003311312041014
643524455133145550
72523065223511263
oct276761246576752
951416824354483
1013123450502634
1141aa69575458a
12157b4b502b2b6
137426c799b704
1433526d72396a
1517b58751d859
hexbef8a9afdea

13123450502634 has 16 divisors (see below), whose sum is σ = 26248356069120. Its totient is φ = 4374240990240.

The previous prime is 13123450502623. The next prime is 13123450502663. The reversal of 13123450502634 is 43620505432131.

It is a junction number, because it is equal to n+sod(n) for n = 13123450502592 and 13123450502601.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60510394 + ... + 60726885.

It is an arithmetic number, because the mean of its divisors is an integer number (1640522254320).

Almost surely, 213123450502634 is an apocalyptic number.

13123450502634 is an abundant number, since it is smaller than the sum of its proper divisors (13124905566486).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13123450502634 is a wasteful number, since it uses less digits than its factorization.

13123450502634 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121255325.

The product of its (nonzero) digits is 259200, while the sum is 39.

Adding to 13123450502634 its reverse (43620505432131), we get a palindrome (56743955934765).

The spelling of 13123450502634 in words is "thirteen trillion, one hundred twenty-three billion, four hundred fifty million, five hundred two thousand, six hundred thirty-four".

Divisors: 1 2 3 6 18041 36082 54123 108246 121237279 242474558 363711837 727423674 2187241750439 4374483500878 6561725251317 13123450502634