Base | Representation |
---|---|
bin | 10011000110001110001… |
… | …010011000101100011111 |
3 | 11122110101221021011200211 |
4 | 103012032022120230133 |
5 | 133000143112100133 |
6 | 2442515121233251 |
7 | 163546154621401 |
oct | 23061612305437 |
9 | 4573357234624 |
10 | 1312350112543 |
11 | 466623475578 |
12 | 192413492827 |
13 | 969a5954442 |
14 | 477378a2b71 |
15 | 2420d2a2bcd |
hex | 1318e298b1f |
1312350112543 has 4 divisors (see below), whose sum is σ = 1312507232128. Its totient is φ = 1312192992960.
The previous prime is 1312350112529. The next prime is 1312350112589. The reversal of 1312350112543 is 3452110532131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312350112543 - 229 = 1311813241631 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312350112523) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78547263 + ... + 78563968.
It is an arithmetic number, because the mean of its divisors is an integer number (328126808032).
Almost surely, 21312350112543 is an apocalyptic number.
1312350112543 is a deficient number, since it is larger than the sum of its proper divisors (157119585).
1312350112543 is an equidigital number, since it uses as much as digits as its factorization.
1312350112543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 157119584.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 1312350112543 its reverse (3452110532131), we get a palindrome (4764460644674).
The spelling of 1312350112543 in words is "one trillion, three hundred twelve billion, three hundred fifty million, one hundred twelve thousand, five hundred forty-three".
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