Base | Representation |
---|---|
bin | 10011000110001110001… |
… | …101111011111111000011 |
3 | 11122110102000000110202120 |
4 | 103012032031323333003 |
5 | 133000143331343043 |
6 | 2442515153215323 |
7 | 163546165546542 |
oct | 23061615737703 |
9 | 4573360013676 |
10 | 1312351043523 |
11 | 466623a50a83 |
12 | 192413861543 |
13 | 969a5bbc110 |
14 | 47737a66159 |
15 | 2420d3d8983 |
hex | 1318e37bfc3 |
1312351043523 has 32 divisors (see below), whose sum is σ = 1892120272896. Its totient is φ = 804295433088.
The previous prime is 1312351043503. The next prime is 1312351043533. The reversal of 1312351043523 is 3253401532131.
It is not a de Polignac number, because 1312351043523 - 26 = 1312351043459 is a prime.
It is a super-2 number, since 2×13123510435232 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1312351043503) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 23122486 + ... + 23179172.
It is an arithmetic number, because the mean of its divisors is an integer number (59128758528).
Almost surely, 21312351043523 is an apocalyptic number.
1312351043523 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1312351043523 is a deficient number, since it is larger than the sum of its proper divisors (579769229373).
1312351043523 is a wasteful number, since it uses less digits than its factorization.
1312351043523 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59123.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 1312351043523 its reverse (3253401532131), we get a palindrome (4565752575654).
The spelling of 1312351043523 in words is "one trillion, three hundred twelve billion, three hundred fifty-one million, forty-three thousand, five hundred twenty-three".
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