1312354531533 has 4 divisors (see below), whose sum is σ = 1749806042048. Its totient is φ = 874903021020.

The previous prime is 1312354531531. The next prime is 1312354531549. The reversal of 1312354531533 is 3351354532131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1312354531533 - 2¹ = 1312354531531 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1312354531491 and 1312354531500.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312354531531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218725755253 + ... + 218725755258.

It is an arithmetic number, because the mean of its divisors is an integer number (437451510512).

Almost surely, 2^{1312354531533} is an apocalyptic number.

It is an amenable number.

1312354531533 is a deficient number, since it is larger than the sum of its proper divisors (437451510515).

1312354531533 is an equidigital number, since it uses as much as digits as its factorization.

1312354531533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 437451510514.

The product of its digits is 243000, while the sum is 39.

The spelling of 1312354531533 in words is "one trillion, three hundred twelve billion, three hundred fifty-four million, five hundred thirty-one thousand, five hundred thirty-three".