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13123625040402 = 232437897525991
BaseRepresentation
bin1011111011111001010100…
…0000100011101000010010
31201110121100222211021100120
42332332111000203220102
53210004141002243102
643524524330131110
72523102443166612
oct276762500435022
951417328737316
1013123625040402
1141aa775226378
12157b543580a96
13742724bac2b6
14335288998a42
1517b5979e86bc
hexbef95023a12

13123625040402 has 16 divisors (see below), whose sum is σ = 26258020421952. Its totient is φ = 4372746623280.

The previous prime is 13123625040397. The next prime is 13123625040419. The reversal of 13123625040402 is 20404052632131.

It is a super-2 number, since 2×131236250404022 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 448748374 + ... + 448777617.

It is an arithmetic number, because the mean of its divisors is an integer number (1641126276372).

Almost surely, 213123625040402 is an apocalyptic number.

13123625040402 is an abundant number, since it is smaller than the sum of its proper divisors (13134395381550).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13123625040402 is a wasteful number, since it uses less digits than its factorization.

13123625040402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 897528433.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 13123625040402 its reverse (20404052632131), we get a palindrome (33527677672533).

The spelling of 13123625040402 in words is "thirteen trillion, one hundred twenty-three billion, six hundred twenty-five million, forty thousand, four hundred two".

Divisors: 1 2 3 6 2437 4874 7311 14622 897525991 1795051982 2692577973 5385155946 2187270840067 4374541680134 6561812520201 13123625040402