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13123875493 = 27763472711
BaseRepresentation
bin11000011100011111…
…00111001010100101
31020212121212221200201
430032033213022211
5203334203003433
610010134110501
7643136046451
oct141617471245
936777787621
1013123875493
1156250a39a3
1226631ab431
131311c54901
148c6db3661
1551c270a7d
hex30e3e72a5

13123875493 has 4 divisors (see below), whose sum is σ = 13124375968. Its totient is φ = 13123375020.

The previous prime is 13123875473. The next prime is 13123875497. The reversal of 13123875493 is 39457832131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 39457832131 = 120511327421.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13123875493 is a prime.

It is a super-2 number, since 2×131238754932 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13123875497) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 208593 + ... + 264118.

It is an arithmetic number, because the mean of its divisors is an integer number (3281093992).

Almost surely, 213123875493 is an apocalyptic number.

It is an amenable number.

13123875493 is a deficient number, since it is larger than the sum of its proper divisors (500475).

13123875493 is an equidigital number, since it uses as much as digits as its factorization.

13123875493 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 500474.

The product of its digits is 544320, while the sum is 46.

The spelling of 13123875493 in words is "thirteen billion, one hundred twenty-three million, eight hundred seventy-five thousand, four hundred ninety-three".

Divisors: 1 27763 472711 13123875493