131239448384999 has 4 divisors (see below), whose sum is σ = 131240517328680. Its totient is φ = 131238379441320.

The previous prime is 131239448384923. The next prime is 131239448385011. The reversal of 131239448384999 is 999483844932131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131239448384999 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131239448384599) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 534287657 + ... + 534533234.

It is an arithmetic number, because the mean of its divisors is an integer number (32810129332170).

Almost surely, 2^{131239448384999} is an apocalyptic number.

131239448384999 is a deficient number, since it is larger than the sum of its proper divisors (1068943681).

131239448384999 is a wasteful number, since it uses less digits than its factorization.

131239448384999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1068943680.

The product of its digits is 1451188224, while the sum is 77.

The spelling of 131239448384999 in words is "one hundred thirty-one trillion, two hundred thirty-nine billion, four hundred forty-eight million, three hundred eighty-four thousand, nine hundred ninety-nine".