1312400441431 has 4 divisors (see below), whose sum is σ = 1312412309032. Its totient is φ = 1312388573832.

The previous prime is 1312400441399. The next prime is 1312400441453. The reversal of 1312400441431 is 1341440042131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312400441431 - 2⁵ = 1312400441399 is a prime.

It is a super-2 number, since 2×1312400441431² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1312400441431.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312400441491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5766345 + ... + 5989618.

It is an arithmetic number, because the mean of its divisors is an integer number (328103077258).

Almost surely, 2^{1312400441431} is an apocalyptic number.

1312400441431 is a deficient number, since it is larger than the sum of its proper divisors (11867601).

1312400441431 is a wasteful number, since it uses less digits than its factorization.

1312400441431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11867600.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1312400441431 its reverse (1341440042131), we get a palindrome (2653840483562).

The spelling of 1312400441431 in words is "one trillion, three hundred twelve billion, four hundred million, four hundred forty-one thousand, four hundred thirty-one".