13124142111101 has 4 divisors (see below), whose sum is σ = 14999019555552. Its totient is φ = 11249264666652.

The previous prime is 13124142111083. The next prime is 13124142111107. The reversal of 13124142111101 is 10111124142131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13124142111101 - 2³⁴ = 13106962241917 is a prime.

It is a super-2 number, since 2×13124142111101² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13124142111107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 937438722215 + ... + 937438722228.

It is an arithmetic number, because the mean of its divisors is an integer number (3749754888888).

Almost surely, 2^{13124142111101} is an apocalyptic number.

It is an amenable number.

13124142111101 is a deficient number, since it is larger than the sum of its proper divisors (1874877444451).

13124142111101 is an equidigital number, since it uses as much as digits as its factorization.

13124142111101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1874877444450.

The product of its (nonzero) digits is 192, while the sum is 23.

Adding to 13124142111101 its reverse (10111124142131), we get a palindrome (23235266253232).

The spelling of 13124142111101 in words is "thirteen trillion, one hundred twenty-four billion, one hundred forty-two million, one hundred eleven thousand, one hundred one".