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1312415041153 = 7011872204053
BaseRepresentation
bin10011000110010010000…
…010000100011010000001
311122110120110102220000011
4103012102002010122001
5133000311222304103
62442525401024521
7163550603533546
oct23062202043201
94573513386004
101312415041153
11466657092387
12192431185141
13969b6238838
1447742364bcd
1524213d2ad6d
hex13192084681

1312415041153 has 4 divisors (see below), whose sum is σ = 1314287245908. Its totient is φ = 1310542836400.

The previous prime is 1312415041123. The next prime is 1312415041163. The reversal of 1312415041153 is 3511405142131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1010813073664 + 301601967489 = 1005392^2 + 549183^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312415041153 - 229 = 1311878170241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1312415041123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936101326 + ... + 936102727.

It is an arithmetic number, because the mean of its divisors is an integer number (328571811477).

Almost surely, 21312415041153 is an apocalyptic number.

It is an amenable number.

1312415041153 is a deficient number, since it is larger than the sum of its proper divisors (1872204755).

1312415041153 is an equidigital number, since it uses as much as digits as its factorization.

1312415041153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1872204754.

The product of its (nonzero) digits is 7200, while the sum is 31.

The spelling of 1312415041153 in words is "one trillion, three hundred twelve billion, four hundred fifteen million, forty-one thousand, one hundred fifty-three".

Divisors: 1 701 1872204053 1312415041153