Base | Representation |
---|---|
bin | 10011000110010010010… |
… | …000110001010111111001 |
3 | 11122110120201200200222022 |
4 | 103012102100301113321 |
5 | 133000313214122403 |
6 | 2442530015404225 |
7 | 163550651355356 |
oct | 23062220612771 |
9 | 4573521620868 |
10 | 1312418895353 |
11 | 466659285075 |
12 | 192432523675 |
13 | 969b6c87c27 |
14 | 47742a8962d |
15 | 2421433cd38 |
hex | 131924315f9 |
1312418895353 has 8 divisors (see below), whose sum is σ = 1314766224288. Its totient is φ = 1310072019264.
The previous prime is 1312418895349. The next prime is 1312418895421. The reversal of 1312418895353 is 3535988142131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1312418895353 - 22 = 1312418895349 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1312418895295 and 1312418895304.
It is not an unprimeable number, because it can be changed into a prime (1312418895343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5980550 + ... + 6196112.
It is an arithmetic number, because the mean of its divisors is an integer number (164345778036).
Almost surely, 21312418895353 is an apocalyptic number.
It is an amenable number.
1312418895353 is a deficient number, since it is larger than the sum of its proper divisors (2347328935).
1312418895353 is a wasteful number, since it uses less digits than its factorization.
1312418895353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 226423.
The product of its digits is 3110400, while the sum is 53.
The spelling of 1312418895353 in words is "one trillion, three hundred twelve billion, four hundred eighteen million, eight hundred ninety-five thousand, three hundred fifty-three".
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