Base | Representation |
---|---|
bin | 1011111011111011011101… |
… | …1110000110111000110111 |
3 | 1201110122212021202110011011 |
4 | 2332332313132012320313 |
5 | 3210011332010243333 |
6 | 43525101542253051 |
7 | 2523122663444236 |
oct | 276766736067067 |
9 | 51418767673134 |
10 | 13124203212343 |
11 | 41aaa41625523 |
12 | 157b685127187 |
13 | 7427b7904682 |
14 | 33530169cb1d |
15 | 17b5cd6539cd |
hex | befb7786e37 |
13124203212343 has 4 divisors (see below), whose sum is σ = 13124292312808. Its totient is φ = 13124114111880.
The previous prime is 13124203212247. The next prime is 13124203212361. The reversal of 13124203212343 is 34321230242131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13124203212343 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13124203222343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44328921 + ... + 44624002.
It is an arithmetic number, because the mean of its divisors is an integer number (3281073078202).
Almost surely, 213124203212343 is an apocalyptic number.
13124203212343 is a deficient number, since it is larger than the sum of its proper divisors (89100465).
13124203212343 is an equidigital number, since it uses as much as digits as its factorization.
13124203212343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89100464.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13124203212343 its reverse (34321230242131), we get a palindrome (47445433454474).
The spelling of 13124203212343 in words is "thirteen trillion, one hundred twenty-four billion, two hundred three million, two hundred twelve thousand, three hundred forty-three".
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