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13124204013 = 34374734671
BaseRepresentation
bin11000011100100001…
…10111010111101101
31020212122111122100010
430032100313113231
5203334244012023
610010145123433
7643141615314
oct141620672755
936778448303
1013124204013
1156252a87a8
122663329579
13131203b2bb
148c705b27b
1551c2d8093
hex30e4375ed

13124204013 has 4 divisors (see below), whose sum is σ = 17498938688. Its totient is φ = 8749469340.

The previous prime is 13124203999. The next prime is 13124204089. The reversal of 13124204013 is 31040242131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13124204013 - 216 = 13124138477 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13124204413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2187367333 + ... + 2187367338.

It is an arithmetic number, because the mean of its divisors is an integer number (4374734672).

Almost surely, 213124204013 is an apocalyptic number.

It is an amenable number.

13124204013 is a deficient number, since it is larger than the sum of its proper divisors (4374734675).

13124204013 is an equidigital number, since it uses as much as digits as its factorization.

13124204013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4374734674.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 13124204013 its reverse (31040242131), we get a palindrome (44164446144).

The spelling of 13124204013 in words is "thirteen billion, one hundred twenty-four million, two hundred four thousand, thirteen".

Divisors: 1 3 4374734671 13124204013