Base | Representation |
---|---|
bin | 111101000111010100… |
… | …0101010100000011111 |
3 | 110112202111001120220002 |
4 | 1322032220222200133 |
5 | 4122240430342143 |
6 | 140143004244515 |
7 | 12324204651131 |
oct | 1721650524037 |
9 | 415674046802 |
10 | 131242043423 |
11 | 507287917a7 |
12 | 2152884073b |
13 | c4b72c997a |
14 | 64d0421051 |
15 | 3631e065b8 |
hex | 1e8ea2a81f |
131242043423 has 8 divisors (see below), whose sum is σ = 138992224128. Its totient is φ = 123662196504.
The previous prime is 131242043419. The next prime is 131242043447. The reversal of 131242043423 is 324340242131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131242043423 - 22 = 131242043419 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131242043453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42581861 + ... + 42584942.
It is an arithmetic number, because the mean of its divisors is an integer number (17374028016).
Almost surely, 2131242043423 is an apocalyptic number.
131242043423 is a deficient number, since it is larger than the sum of its proper divisors (7750180705).
131242043423 is an equidigital number, since it uses as much as digits as its factorization.
131242043423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 85166893.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 131242043423 its reverse (324340242131), we get a palindrome (455582285554).
The spelling of 131242043423 in words is "one hundred thirty-one billion, two hundred forty-two million, forty-three thousand, four hundred twenty-three".
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