Base | Representation |
---|---|
bin | 1011111011111011100000… |
… | …0100001111111110011011 |
3 | 1201110122212222120102210002 |
4 | 2332332320010033332123 |
5 | 3210011342040223120 |
6 | 43525102540443215 |
7 | 2523123144440033 |
oct | 276767004177633 |
9 | 51418788512702 |
10 | 13124213211035 |
11 | 41aaa47234703 |
12 | 157b68854950b |
13 | 7427b99c5764 |
14 | 335302b428c3 |
15 | 17b5ce47b375 |
hex | befb810ff9b |
13124213211035 has 16 divisors (see below), whose sum is σ = 16257342373632. Its totient is φ = 10160523408000.
The previous prime is 13124213211019. The next prime is 13124213211037. The reversal of 13124213211035 is 53011231242131.
It is not a de Polignac number, because 13124213211035 - 24 = 13124213211019 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13124213210989 and 13124213211007.
It is not an unprimeable number, because it can be changed into a prime (13124213211037) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9901157 + ... + 11148153.
It is an arithmetic number, because the mean of its divisors is an integer number (1016083898352).
Almost surely, 213124213211035 is an apocalyptic number.
13124213211035 is a deficient number, since it is larger than the sum of its proper divisors (3133129162597).
13124213211035 is a wasteful number, since it uses less digits than its factorization.
13124213211035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1314934.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 13124213211035 its reverse (53011231242131), we get a palindrome (66135444453166).
The spelling of 13124213211035 in words is "thirteen trillion, one hundred twenty-four billion, two hundred thirteen million, two hundred eleven thousand, thirty-five".
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