13124213211034 has 4 divisors (see below), whose sum is σ = 19686319816554. Its totient is φ = 6562106605516.

The previous prime is 13124213211019. The next prime is 13124213211037. The reversal of 13124213211034 is 43011231242131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 7155705250225 + 5968507960809 = 2675015^2 + 2443053^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13124213210993 and 13124213211011.

It is not an unprimeable number, because it can be changed into a prime (13124213211037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3281053302757 + ... + 3281053302760.

Almost surely, 2^{13124213211034} is an apocalyptic number.

13124213211034 is a deficient number, since it is larger than the sum of its proper divisors (6562106605520).

13124213211034 is an equidigital number, since it uses as much as digits as its factorization.

13124213211034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6562106605519.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 13124213211034 its reverse (43011231242131), we get a palindrome (56135444453165).

The spelling of 13124213211034 in words is "thirteen trillion, one hundred twenty-four billion, two hundred thirteen million, two hundred eleven thousand, thirty-four".