13124220433 has 4 divisors (see below), whose sum is σ = 13125456448. Its totient is φ = 13122984420.

The previous prime is 13124220409. The next prime is 13124220443. The reversal of 13124220433 is 33402242131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13124220433 - 2⁹ = 13124219921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13124220398 and 13124220407.

It is not an unprimeable number, because it can be changed into a prime (13124220443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 601941 + ... + 623362.

It is an arithmetic number, because the mean of its divisors is an integer number (3281364112).

Almost surely, 2^13124220433 is an apocalyptic number.

It is an amenable number.

13124220433 is a deficient number, since it is larger than the sum of its proper divisors (1236015).

13124220433 is a wasteful number, since it uses less digits than its factorization.

13124220433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1236014.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 13124220433 its reverse (33402242131), we get a palindrome (46526462564).

The spelling of 13124220433 in words is "thirteen billion, one hundred twenty-four million, two hundred twenty thousand, four hundred thirty-three".