13124230220401 has 4 divisors (see below), whose sum is σ = 13126549404400. Its totient is φ = 13121911036404.

The previous prime is 13124230220399. The next prime is 13124230220473. The reversal of 13124230220401 is 10402203242131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13124230220401 - 2¹ = 13124230220399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13124230200401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1159583511 + ... + 1159594828.

It is an arithmetic number, because the mean of its divisors is an integer number (3281637351100).

Almost surely, 2^{13124230220401} is an apocalyptic number.

It is an amenable number.

13124230220401 is a deficient number, since it is larger than the sum of its proper divisors (2319183999).

13124230220401 is an equidigital number, since it uses as much as digits as its factorization.

13124230220401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2319183998.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13124230220401 its reverse (10402203242131), we get a palindrome (23526433462532).

The spelling of 13124230220401 in words is "thirteen trillion, one hundred twenty-four billion, two hundred thirty million, two hundred twenty thousand, four hundred one".