Base | Representation |
---|---|
bin | 1011111011111011101010… |
… | …0100111001010010101001 |
3 | 1201110122222220210221221210 |
4 | 2332332322210321102221 |
5 | 3210011433330321210 |
6 | 43525111043223333 |
7 | 2523124165413240 |
oct | 276767244712251 |
9 | 51418886727853 |
10 | 13124255323305 |
11 | 41aaa68a88235 |
12 | 157b69a677b49 |
13 | 7427c564b869 |
14 | 335308585957 |
15 | 17b5d2ee8e20 |
hex | befba9394a9 |
13124255323305 has 32 divisors (see below), whose sum is σ = 24007491145728. Its totient is φ = 5997446366400.
The previous prime is 13124255323297. The next prime is 13124255323331. The reversal of 13124255323305 is 50332355242131.
It is not a de Polignac number, because 13124255323305 - 23 = 13124255323297 is a prime.
It is a super-2 number, since 2×131242553233052 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 22768261 + ... + 23337570.
It is an arithmetic number, because the mean of its divisors is an integer number (750234098304).
Almost surely, 213124255323305 is an apocalyptic number.
13124255323305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13124255323305 is a deficient number, since it is larger than the sum of its proper divisors (10883235822423).
13124255323305 is a wasteful number, since it uses less digits than its factorization.
13124255323305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46108557.
The product of its (nonzero) digits is 324000, while the sum is 39.
The spelling of 13124255323305 in words is "thirteen trillion, one hundred twenty-four billion, two hundred fifty-five million, three hundred twenty-three thousand, three hundred five".
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