13124301431445 has 12 divisors (see below), whose sum is σ = 22748789147916. Its totient is φ = 6999627430080.

The previous prime is 13124301431419. The next prime is 13124301431467. The reversal of 13124301431445 is 54413410342131.

13124301431445 is a `hidden beast` number, since 1 + 31 + 2 + 4 + 301 + 4 + 314 + 4 + 5 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 8371491582609 + 4752809848836 = 2893353^2 + 2180094^2 .

It is not a de Polignac number, because 13124301431445 - 2⁵ = 13124301431413 is a prime.

It is a super-3 number, since 3×13124301431445³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 145825571416 + ... + 145825571505.

It is an arithmetic number, because the mean of its divisors is an integer number (1895732428993).

Almost surely, 2^{13124301431445} is an apocalyptic number.

13124301431445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

13124301431445 is a deficient number, since it is larger than the sum of its proper divisors (9624487716471).

13124301431445 is a wasteful number, since it uses less digits than its factorization.

13124301431445 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 291651142932 (or 291651142929 counting only the distinct ones).

The product of its (nonzero) digits is 69120, while the sum is 36.

Adding to 13124301431445 its reverse (54413410342131), we get a palindrome (67537711773576).

The spelling of 13124301431445 in words is "thirteen trillion, one hundred twenty-four billion, three hundred one million, four hundred thirty-one thousand, four hundred forty-five".