Base | Representation |
---|---|
bin | 1011111011111011110101… |
… | …0101010000001001000010 |
3 | 1201110200010010210201212201 |
4 | 2332332331111100021002 |
5 | 3210012032144213432 |
6 | 43525115414143414 |
7 | 2523125266362304 |
oct | 276767525201102 |
9 | 51420103721781 |
10 | 13124301554242 |
11 | 41aaa9209421a |
12 | 157b6b2051b6a |
13 | 7428020b7548 |
14 | 33531077b974 |
15 | 17b5d70cbee7 |
hex | befbd550242 |
13124301554242 has 4 divisors (see below), whose sum is σ = 19686452331366. Its totient is φ = 6562150777120.
The previous prime is 13124301554219. The next prime is 13124301554333. The reversal of 13124301554242 is 24245510342131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 7702906218921 + 5421395335321 = 2775411^2 + 2328389^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3281075388559 + ... + 3281075388562.
Almost surely, 213124301554242 is an apocalyptic number.
13124301554242 is a deficient number, since it is larger than the sum of its proper divisors (6562150777124).
13124301554242 is an equidigital number, since it uses as much as digits as its factorization.
13124301554242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6562150777123.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 13124301554242 its reverse (24245510342131), we get a palindrome (37369811896373).
The spelling of 13124301554242 in words is "thirteen trillion, one hundred twenty-four billion, three hundred one million, five hundred fifty-four thousand, two hundred forty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •