13124331041431 has 16 divisors (see below), whose sum is σ = 13233910563328. Its totient is φ = 13015209664800.

The previous prime is 13124331041321. The next prime is 13124331041461. The reversal of 13124331041431 is 13414013342131.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13124331041431 is a prime.

It is a super-2 number, since 2×13124331041431² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13124331041393 and 13124331041402.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13124331041461) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 93925840 + ... + 94065466.

It is an arithmetic number, because the mean of its divisors is an integer number (827119410208).

Almost surely, 2^{13124331041431} is an apocalyptic number.

13124331041431 is a deficient number, since it is larger than the sum of its proper divisors (109579521897).

13124331041431 is a wasteful number, since it uses less digits than its factorization.

13124331041431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 141262.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 13124331041431 its reverse (13414013342131), we get a palindrome (26538344383562).

The spelling of 13124331041431 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-one million, forty-one thousand, four hundred thirty-one".