13124340401001 has 4 divisors (see below), whose sum is σ = 17499120534672. Its totient is φ = 8749560267332.

The previous prime is 13124340400981. The next prime is 13124340401041. The reversal of 13124340401001 is 10010404342131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13124340401001 - 2⁹ = 13124340400489 is a prime.

It is a super-2 number, since 2×13124340401001² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13124340401041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2187390066831 + ... + 2187390066836.

It is an arithmetic number, because the mean of its divisors is an integer number (4374780133668).

Almost surely, 2^{13124340401001} is an apocalyptic number.

It is an amenable number.

13124340401001 is a deficient number, since it is larger than the sum of its proper divisors (4374780133671).

13124340401001 is an equidigital number, since it uses as much as digits as its factorization.

13124340401001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4374780133670.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 13124340401001 its reverse (10010404342131), we get a palindrome (23134744743132).

The spelling of 13124340401001 in words is "thirteen trillion, one hundred twenty-four billion, three hundred forty million, four hundred one thousand, one".