1312440113 has 4 divisors (see below), whose sum is σ = 1337203188. Its totient is φ = 1287677040.

The previous prime is 1312440091. The next prime is 1312440121. The reversal of 1312440113 is 3110442131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 810142369 + 502297744 = 28463^2 + 22412^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312440113 - 2⁶ = 1312440049 is a prime.

It is a super-2 number, since 2×1312440113² = 3444998100422905538, which contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1312440133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12381458 + ... + 12381563.

It is an arithmetic number, because the mean of its divisors is an integer number (334300797).

Almost surely, 2^1312440113 is an apocalyptic number.

It is an amenable number.

1312440113 is a deficient number, since it is larger than the sum of its proper divisors (24763075).

1312440113 is an equidigital number, since it uses as much as digits as its factorization.

1312440113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24763074.

The product of its (nonzero) digits is 288, while the sum is 20.

The square root of 1312440113 is about 36227.6153369222. The cubic root of 1312440113 is about 1094.8631322576.

Adding to 1312440113 its reverse (3110442131), we get a palindrome (4422882244).

The spelling of 1312440113 in words is "one billion, three hundred twelve million, four hundred forty thousand, one hundred thirteen".