Base | Representation |
---|---|
bin | 1011111011111100001111… |
… | …1100100011011001101001 |
3 | 1201110200101212121101100010 |
4 | 2332333003330203121221 |
5 | 3210012244101120131 |
6 | 43525134420402133 |
7 | 2523131114515614 |
oct | 276770374433151 |
9 | 51420355541303 |
10 | 13124412520041 |
11 | 4200039795499 |
12 | 157b723246349 |
13 | 74281c09a394 |
14 | 3353213c517b |
15 | 17b5e1beab46 |
hex | befc3f23669 |
13124412520041 has 16 divisors (see below), whose sum is σ = 17974743260544. Its totient is φ = 8511912820224.
The previous prime is 13124412520013. The next prime is 13124412520057. The reversal of 13124412520041 is 14002521442131.
It is not a de Polignac number, because 13124412520041 - 231 = 13122265036393 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13124412519990 and 13124412520008.
It is not an unprimeable number, because it can be changed into a prime (13124412520741) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7691016 + ... + 9241241.
It is an arithmetic number, because the mean of its divisors is an integer number (1123421453784).
Almost surely, 213124412520041 is an apocalyptic number.
It is an amenable number.
13124412520041 is a deficient number, since it is larger than the sum of its proper divisors (4850330740503).
13124412520041 is a wasteful number, since it uses less digits than its factorization.
13124412520041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16939280.
The product of its (nonzero) digits is 7680, while the sum is 30.
Adding to 13124412520041 its reverse (14002521442131), we get a palindrome (27126933962172).
The spelling of 13124412520041 in words is "thirteen trillion, one hundred twenty-four billion, four hundred twelve million, five hundred twenty thousand, forty-one".
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