131244340144031 has 4 divisors (see below), whose sum is σ = 132202328028432. Its totient is φ = 130286352259632.

The previous prime is 131244340144019. The next prime is 131244340144061. The reversal of 131244340144031 is 130441043442131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131244340144031 - 2¹⁴ = 131244340127647 is a prime.

It is a super-2 number, since 2×131244340144031² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131244340143982 and 131244340144000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131244340144061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 478993941995 + ... + 478993942268.

It is an arithmetic number, because the mean of its divisors is an integer number (33050582007108).

Almost surely, 2^{131244340144031} is an apocalyptic number.

131244340144031 is a deficient number, since it is larger than the sum of its proper divisors (957987884401).

131244340144031 is an equidigital number, since it uses as much as digits as its factorization.

131244340144031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 957987884400.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 131244340144031 its reverse (130441043442131), we get a palindrome (261685383586162).

The spelling of 131244340144031 in words is "one hundred thirty-one trillion, two hundred forty-four billion, three hundred forty million, one hundred forty-four thousand, thirty-one".