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13124443330423 = 71184851314513
BaseRepresentation
bin1011111011111100010111…
…0010000101011101110111
31201110200111000120201020101
42332333011302011131313
53210012324443033143
643525141441014531
72523131640431035
oct276770562053567
951420430521211
1013124443330423
114200055119817
12157b731624447
13742825597189
14335325525555
1517b5e4784b4d
hexbefc5c85777

13124443330423 has 4 divisors (see below), whose sum is σ = 13309294645008. Its totient is φ = 12939592015840.

The previous prime is 13124443330399. The next prime is 13124443330543. The reversal of 13124443330423 is 32403334442131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13124443330423 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13124443340423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92425657186 + ... + 92425657327.

It is an arithmetic number, because the mean of its divisors is an integer number (3327323661252).

Almost surely, 213124443330423 is an apocalyptic number.

13124443330423 is a deficient number, since it is larger than the sum of its proper divisors (184851314585).

13124443330423 is an equidigital number, since it uses as much as digits as its factorization.

13124443330423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 184851314584.

The product of its (nonzero) digits is 248832, while the sum is 37.

Adding to 13124443330423 its reverse (32403334442131), we get a palindrome (45527777772554).

The spelling of 13124443330423 in words is "thirteen trillion, one hundred twenty-four billion, four hundred forty-three million, three hundred thirty thousand, four hundred twenty-three".

Divisors: 1 71 184851314513 13124443330423