Base | Representation |
---|---|
bin | 1011111011111100011000… |
… | …1100111000000110010011 |
3 | 1201110200111111210112011101 |
4 | 2332333012030320012103 |
5 | 3210012333242303210 |
6 | 43525142251325231 |
7 | 2523132054221452 |
oct | 276770614700623 |
9 | 51420444715141 |
10 | 13124450353555 |
11 | 4200059086362 |
12 | 157b733a50817 |
13 | 742826b85a88 |
14 | 335326432b99 |
15 | 17b5e51c0a3a |
hex | befc6338193 |
13124450353555 has 8 divisors (see below), whose sum is σ = 15749571670992. Its totient is φ = 10499406118368.
The previous prime is 13124450353541. The next prime is 13124450353583. The reversal of 13124450353555 is 55535305442131.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13124450353555 - 25 = 13124450353523 is a prime.
It is a super-3 number, since 3×131244503535553 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18895312 + ... + 19577581.
It is an arithmetic number, because the mean of its divisors is an integer number (1968696458874).
Almost surely, 213124450353555 is an apocalyptic number.
13124450353555 is a deficient number, since it is larger than the sum of its proper divisors (2625121317437).
13124450353555 is an equidigital number, since it uses as much as digits as its factorization.
13124450353555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38541125.
The product of its (nonzero) digits is 2700000, while the sum is 46.
Adding to 13124450353555 its reverse (55535305442131), we get a palindrome (68659755795686).
The spelling of 13124450353555 in words is "thirteen trillion, one hundred twenty-four billion, four hundred fifty million, three hundred fifty-three thousand, five hundred fifty-five".
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