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13124479747 = 97113516457
BaseRepresentation
bin11000011100100011…
…11010101100000011
31020212200000122120111
430032101322230003
5203334331322442
610010155052151
7643144144231
oct141621725403
936780018514
1013124479747
115625476985
122663441057
131312106962
148c70cd951
1551c33eb17
hex30e47ab03

13124479747 has 4 divisors (see below), whose sum is σ = 13137997176. Its totient is φ = 13110962320.

The previous prime is 13124479649. The next prime is 13124479777. The reversal of 13124479747 is 74797442131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13124479747 is a prime.

It is a Smith number, since the sum of its digits (49) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13124479747.

It is not an unprimeable number, because it can be changed into a prime (13124479777) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6757258 + ... + 6759199.

It is an arithmetic number, because the mean of its divisors is an integer number (3284499294).

Almost surely, 213124479747 is an apocalyptic number.

13124479747 is a deficient number, since it is larger than the sum of its proper divisors (13517429).

13124479747 is an equidigital number, since it uses as much as digits as its factorization.

13124479747 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13517428.

The product of its digits is 1185408, while the sum is 49.

The spelling of 13124479747 in words is "thirteen billion, one hundred twenty-four million, four hundred seventy-nine thousand, seven hundred forty-seven".

Divisors: 1 971 13516457 13124479747