Base | Representation |
---|---|
bin | 1011111011111110101111… |
… | …0110111001011001000111 |
3 | 1201110202010112120212212221 |
4 | 2332333223312321121013 |
5 | 3210020132011012040 |
6 | 43525325100353211 |
7 | 2523153525210355 |
oct | 276775366713107 |
9 | 51422115525787 |
10 | 13125082125895 |
11 | 4200352765263 |
12 | 157b88b545807 |
13 | 7428c7a2726c |
14 | 3353862ca7d5 |
15 | 17b6308b774a |
hex | befebdb9647 |
13125082125895 has 4 divisors (see below), whose sum is σ = 15750098551080. Its totient is φ = 10500065700712.
The previous prime is 13125082125893. The next prime is 13125082125937. The reversal of 13125082125895 is 59852128052131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13125082125895 - 21 = 13125082125893 is a prime.
It is a super-2 number, since 2×131250821258952 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13125082125893) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1312508212585 + ... + 1312508212594.
It is an arithmetic number, because the mean of its divisors is an integer number (3937524637770).
Almost surely, 213125082125895 is an apocalyptic number.
13125082125895 is a deficient number, since it is larger than the sum of its proper divisors (2625016425185).
13125082125895 is an equidigital number, since it uses as much as digits as its factorization.
13125082125895 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2625016425184.
The product of its (nonzero) digits is 1728000, while the sum is 52.
The spelling of 13125082125895 in words is "thirteen trillion, one hundred twenty-five billion, eighty-two million, one hundred twenty-five thousand, eight hundred ninety-five".
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